Graph x^2-2

Problem

y=x2−2

Solution

1. Identify the type of function, which is a quadratic function in the form y=a*x2+b*x+c

2. Determine the vertex of the parabola. Since b=0 the xcoordinate of the vertex is x=0

3. Calculate the ycoordinate of the vertex by substituting x=0 into the equation.

y=0−2

y=−2

4. Find the yintercept by setting x=0 which is (0,−2)

5. Find the xintercepts by setting y=0 and solving for x

x2−2=0

x2=2

x=±√(,2)

6. Plot additional points to determine the shape. For x=1 y=−1 For x=2 y=2

7. Sketch the graph as a parabola opening upwards with its vertex at (0,−2)

Final Answer

y=x2−2

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