Graph natural log of 9x
Problem
Solution
Identify the domain of the function. Since the argument of a natural logarithm must be positive, we set
9*x>0 which meansx>0 Determine the vertical asymptote by finding where the argument equals zero. As
x approaches0 from the right,y approaches−∞ so the vertical asymptote isx=0 Find the x-intercept by setting
y=0 Solving0=ln(9*x) givese0=9*x which simplifies to1 = 9x,o*r = \frac{1}{9}$.Calculate additional points to determine the shape of the curve. For example, if
x=1 y=ln(9)≈2.20 Ifx=e/9≈0.30 y=ln(e)=1 Apply the product rule for logarithms to understand the transformation. The function can be rewritten as
y=ln(x)+ln(9) which is a vertical shift of the standardy=ln(x) graph upward byln(9)≈2.20 units.Sketch the graph starting near the vertical asymptote
x=0 passing through(1/9,0) and increasing slowly asx increases.
Final Answer
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