Graph natural log of 8x
Problem
Solution
Identify the domain of the function. Since the argument of a natural logarithm must be positive, we set
8*x>0 which meansx>0 Determine the vertical asymptote by finding where the argument equals zero. As
x approaches0 from the right,y approaches−∞ so the vertical asymptote isx=0 Find the x-intercept by setting
y=0 Solving0=ln(8*x) givese0=8*x which simplifies to1 = 8x,o*r = \frac{1}{8}$.Calculate additional points to determine the shape. For example, if
x=e/8 theny=ln(e)=1 Ifx=1 theny=ln(8)≈2.08 Sketch the curve starting near the vertical asymptote
x=0 passing through(1/8,0) and increasing slowly asx increases.
Final Answer
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