Graph natural log of 5x
Problem
Solution
Identify the domain of the function. Since the argument of a natural logarithm must be positive, we set
5*x>0 which meansx>0 Determine the vertical asymptote by finding where the argument equals zero. As
x approaches0 from the right,y approaches−∞ so the vertical asymptote isx=0 Find the x-intercept by setting
y=0 Solving0=ln(5*x) givese0=5*x which simplifies to1 = 5x,s(o) = \frac{1}{5}o*r .2$.Calculate additional points to determine the shape. For
x=1 y=ln(5)≈1.61 Forx=e/5≈0.54 y=ln(e)=1 Sketch the curve starting near the vertical asymptote
x=0 passing through(0.2,0) and(1,1.61) and continuing to increase slowly asx increases.
Final Answer
Want more problems? Check here!