Graph f(x)=x^3
Problem
Solution
Identify the function type as a cubic function, which is an odd function because
ƒ*(−x)=−ƒ(x) This means the graph is symmetric about the origin.Determine the domain and range. For
ƒ(x)=x3 both the domain and the range are all real numbers,(−∞,∞) Calculate key points to plot. Choose a variety of
x values to see the shape:
If
x=−2 ƒ*(−2)=(−2)3=−8 If
x=−1 ƒ*(−1)=(−1)3=−1 If
x=0 ƒ(0)=0=0 If
x=1 ƒ(1)=1=1 If
x=2 ƒ(2)=2=8
Analyze the behavior. As
x→∞ ƒ(x)→∞ Asx→−∞ ƒ(x)→−∞ The graph passes through the origin(0,0) which is an inflection point where the curve changes from concave down to concave up.Sketch the curve by connecting the points
(−2,−8) (−1,−1) (0,0) (1,1) and(2,8) with a smooth, continuous "S" shaped line.
Final Answer
To graph
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