Find the x and y Intercepts (y+4)^2=-4(x+2)

Problem

(y+4)2=−4*(x+2)

Solution

1. Find the y-intercept by setting x=0 in the equation.

(y+4)2=−4*(0+2)

2. Simplify the right side of the equation.

(y+4)2=−8

3. Solve for y by taking the square root of both sides.

y+4=±√(,−8)

y=−4±2*i√(,2)

Since the solutions are imaginary, there are no real y-intercepts.

4. Find the x-intercept by setting y=0 in the equation.

(0+4)2=−4*(x+2)

5. Simplify the left side of the equation.

16=−4*(x+2)

6. Divide both sides by −4

−4=x+2

7. Solve for x by subtracting 2 from both sides.

x=−6

Final Answer

x-intercept: *(−6,0), y-intercept: None

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