Find the x and y Intercepts y=x^2+4x-12

Problem

y=x2+4*x−12

Solution

1. Find the y-intercept by setting x=0 in the equation.

y=(0)2+4*(0)−12

y=−12

2. Find the x-intercepts by setting y=0 and solving the resulting quadratic equation.

0=x2+4*x−12

3. Factor the quadratic expression by finding two numbers that multiply to −12 and add to 4

0=(x+6)*(x−2)

4. Apply the zero product property by setting each factor equal to zero.

x+6=0⇒x=−6

x−2=0⇒x=2

Final Answer

x-intercepts: *(−6,0),(2,0); y-intercept: *(0,−12)

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