Find the x and y Intercepts y=x^2-4x-12

Problem

y=x2−4*x−12

Solution

1. Find the y-intercept by setting x=0 in the equation.

y=0−4*(0)−12

y=−12

2. Find the x-intercepts by setting y=0 and solving the resulting quadratic equation.

0=x2−4*x−12

3. Factor the quadratic expression by finding two numbers that multiply to −12 and add to −4

0=(x−6)*(x+2)

4. Apply the zero product property by setting each factor equal to zero.

x−6=0⇒x=6

x+2=0⇒x=−2

Final Answer

x-intercepts: *(6,0),(−2,0); y-intercept: *(0,−12)

Want more problems? Check here!