Find the Vertex y=x^2+8x+12

Problem

y=x2+8*x+12

Solution

1. Identify the coefficients of the quadratic equation in the form y=a*x2+b*x+c where a=1 b=8 and c=12

2. Calculate the x-coordinate of the vertex using the formula x=−b/(2*a)

x=−8/(2*(1))

x=−4

3. Substitute the x-coordinate back into the original equation to find the y-coordinate of the vertex.

y=(−4)2+8*(−4)+12

4. Simplify the expression to solve for y

y=16−32+12

y=−4

5. State the vertex as an ordered pair (x,y)

Final Answer

Vertex=(−4,−4)

Want more problems? Check here!