Find the Vertex y=x^2+5

Problem

y=x2+5

Solution

1. Identify the coefficients of the quadratic equation in the standard form y=a*x2+b*x+c

2. Determine the values of a b and c which are a=1 b=0 and c=5

3. Calculate the xcoordinate of the vertex using the formula x=(−b)/(2*a)

x=(−0)/(2*(1))

x=0

4. Substitute the xcoordinate back into the original equation to find the ycoordinate.

y=(0)2+5

y=5

5. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(0,5)

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