Find the Vertex y=x^2+4x-7

Problem

y=x2+4*x−7

Solution

1. Identify the coefficients of the quadratic equation in the form y=a*x2+b*x+c

a=1

b=4

c=−7

2. Calculate the x-coordinate of the vertex using the formula x=−b/(2*a)

x=−4/(2*(1))

x=−2

3. Substitute the x-coordinate back into the original equation to find the y-coordinate.

y=(−2)2+4*(−2)−7

4. Simplify the expression to determine the value of y

y=4−8−7

y=−11

Final Answer

Vertex=(−2,−11)

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