Find the Vertex y=x^2+4x-5

Problem

y=x2+4*x−5

Solution

1. Identify the coefficients of the quadratic equation in the form y=a*x2+b*x+c Here, a=1 b=4 and c=−5

2. Calculate the x-coordinate of the vertex using the formula x=−b/(2*a)

x=−4/(2*(1))

x=−2

3. Substitute the x-coordinate back into the original equation to find the y-coordinate.

y=(−2)2+4*(−2)−5

4. Simplify the expression to solve for y

y=4−8−5

y=−9

5. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(−2,−9)

Want more problems? Check here!