Find the Vertex y=-x^2+2x-3

Problem

y=−x2+2*x−3

Solution

1. Identify the coefficients of the quadratic equation in the form y=a*x2+b*x+c

a=−1

b=2

c=−3

2. Calculate the x-coordinate of the vertex using the formula x=(−b)/(2*a)

x=(−2)/(2*(−1))

x=(−2)/(−2)

x=1

3. Substitute the x-coordinate back into the original equation to find the y-coordinate.

y=−(1)2+2*(1)−3

y=−1+2−3

y=−2

4. State the vertex as the ordered pair (x,y)

Vertex=(1,−2)

Final Answer

Vertex of *y=−x2+2*x−3=(1,−2)

Want more problems? Check here!