Find the Vertex y=x^2+2x-1

Problem

y=x2+2*x−1

Solution

1. Identify the coefficients of the quadratic equation in the form y=a*x2+b*x+c Here, a=1 b=2 and c=−1

2. Calculate the xcoordinate of the vertex using the formula x=(−b)/(2*a)

x=(−2)/(2*(1))

x=−1

3. Substitute the xcoordinate back into the original equation to find the ycoordinate.

y=(−1)2+2*(−1)−1

4. Simplify the expression to determine the value of y

y=1−2−1

y=−2

5. State the vertex as the ordered pair (x,y)

Vertex=(−1,−2)

Final Answer

Vertex of *y=x2+2*x−1=(−1,−2)

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