Find the Vertex y=x^2-8x+5

Problem

y=x2−8*x+5

Solution

1. Identify the coefficients of the quadratic equation in the form y=a*x2+b*x+c Here, a=1 b=−8 and c=5

2. Calculate the x-coordinate of the vertex using the formula x=(−b)/(2*a)

x=(−(−8))/(2*(1))

x=8/2

x=4

3. Substitute the x-coordinate back into the original equation to find the y-coordinate of the vertex.

y=(4)2−8*(4)+5

4. Simplify the expression to find the value of y

y=16−32+5

y=−11

5. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(4,−11)

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