Find the Vertex y=x^2-6

Problem

y=x2−6

Solution

1. Identify the coefficients of the quadratic equation in the standard form y=a*x2+b*x+c

2. Determine the values of a b and c which are a=1 b=0 and c=−6

3. Calculate the xcoordinate of the vertex using the formula x=−b/(2*a)

x=−0/(2*(1))

x=0

4. Substitute the xcoordinate back into the original equation to find the ycoordinate.

y=(0)2−6

y=−6

5. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(0,−6)

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