Find the Vertex y=x^2-10x+21

Problem

y=x2−10*x+21

Solution

1. Identify the coefficients of the quadratic equation in the form y=a*x2+b*x+c where a=1 b=−10 and c=21

2. Calculate the x-coordinate of the vertex using the formula x=(−b)/(2*a)

x=(−(−10))/(2*(1))

x=10/2

x=5

3. Substitute the x-coordinate back into the original equation to find the y-coordinate of the vertex.

y=(5)2−10*(5)+21

y=25−50+21

y=−4

4. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(5,−4)

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