Find the Vertex y=-8x^2+8

Problem

y=−8*x2+8

Solution

1. Identify the coefficients of the quadratic equation in the standard form y=a*x2+b*x+c

2. Determine the values of a b and c which are a=−8 b=0 and c=8

3. Calculate the xcoordinate of the vertex using the formula x=(−b)/(2*a)

x=(−0)/(2*(−8))

x=0

4. Substitute the xvalue back into the original equation to find the ycoordinate of the vertex.

y=−8*(0)2+8

y=8

5. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(0,8)

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