Find the Vertex y=1/4x^2

Problem

y=1/4*x2

Solution

1. Identify the form of the quadratic equation, which is y=a*x2+b*x+c

2. Determine the coefficients from the given equation y=1/4*x2+0*x+0 where a=1/4 b=0 and c=0

3. Calculate the xcoordinate of the vertex using the formula x=−b/(2*a)

x=−0/(2*(1/4))

x=0

4. Substitute the xcoordinate back into the original equation to find the ycoordinate.

y=1/4*(0)2

y=0

5. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(0,0)

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