Find the Vertex x^2+8x+15

Problem

x2+8*x+15

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c

a=1

b=8

c=15

2. Apply the formula for the x-coordinate of the vertex, which is x=(−b)/(2*a)

x=(−8)/(2*(1))

x=−4

3. Substitute the x-coordinate back into the original expression to find the y-coordinate.

y=(−4)2+8*(−4)+15

y=16−32+15

y=−1

4. State the vertex as an ordered pair (x,y)

Vertex=(−4,−1)

Final Answer

Vertex of *x2+8*x+15=(−4,−1)

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