Find the Vertex f(x)=x^2+4x+3

Problem

ƒ(x)=x2+4*x+3

Solution

1. Identify the coefficients of the quadratic function in the form ƒ(x)=a*x2+b*x+c where a=1 b=4 and c=3

2. Calculate the x-coordinate of the vertex using the formula x=−b/(2*a)

x=−4/(2*(1))

x=−2

3. Substitute the x-coordinate back into the original function to find the y-coordinate, ƒ*(−2)

ƒ*(−2)=(−2)2+4*(−2)+3

ƒ*(−2)=4−8+3

ƒ*(−2)=−1

4. State the vertex as the ordered pair (x,y)

Final Answer

Vertex=(−2,−1)

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