Find the Vertex f(x)=(x-5)^2+9

Problem

ƒ(x)=(x−5)2+9

Solution

1. Identify the form of the quadratic function. The given function ƒ(x)=(x−5)2+9 is written in vertex form.

2. Recall the standard vertex form equation. The vertex form of a parabola is given by ƒ(x)=a*(x−h)2+k where the point (h,k) represents the vertex.

3. Compare the given function to the standard form. In the expression (x−5)2+9 the value of h is 5 and the value of k is 9

4. Extract the coordinates of the vertex. Since h=5 and k=9 the vertex is the point (5,9)

Final Answer

Vertex=(5,9)

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