Find the Vertex f(x)=(x-4)^2-1

Problem

ƒ(x)=(x−4)2−1

Solution

1. Identify the form of the quadratic function. The given function ƒ(x)=(x−4)2−1 is written in vertex form.

2. Recall the vertex form equation. The vertex form of a quadratic function is ƒ(x)=a*(x−h)2+k where the point (h,k) represents the vertex of the parabola.

3. Extract the values of h and k from the given function. By comparing ƒ(x)=(x−4)2−1 to the standard vertex form, we see that h=4 and k=−1

4. State the vertex. The vertex is the coordinate pair (h,k)

Final Answer

Vertex=(4,−1)

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