Find the Tangent Line at the Point y=x^3-2x , (2,4)

Problem

y=x3−2*x,(2,4)

Solution

1. Identify the function ƒ(x)=x3−2*x and the given point ((x_1),(y_1))=(2,4)

2. Find the derivative of the function to determine the slope formula using the power rule.

(d(x3)−2*x)/d(x)=3*x2−2

3. Calculate the slope m by substituting the xcoordinate of the given point into the derivative.

m=3*(2)2−2

m=3*(4)−2

m=10

4. Apply the point-slope formula y−(y_1)=m*(x−(x_1)) using the point (2,4) and the slope m=10

y−4=10*(x−2)

5. Simplify the equation into slope-intercept form y=m*x+b

y−4=10*x−20

y=10*x−16

Final Answer

y=10*x−16

Want more problems? Check here!