Find the Prime Factorization 99

Problem

99

Solution

1. Identify the smallest prime number that divides 99 Since 99 is odd, it is not divisible by 2

2. Check for divisibility by 3 The sum of the digits 9 + 9 = 18i*s(d(i))*v*i*s(i)*b*l*e*b*y,s(o)9i*s(d(i))*v*i*s(i)*b*l*e*b*y$.

3. Divide 99 by 3 to find the next factor.

99÷3=33

4. Repeat the process for 33 Since 3 + 3 = 6i*s(d(i))*v*i*s(i)*b*l*e*b*y,d(i)*v*i*d(e)3b*y$.

33÷3=11

5. Identify the remaining factor. Since 11 is a prime number, the process is complete.

6. Write the prime factorization by multiplying the prime factors found.

99=3⋅3⋅11

7. Simplify the expression using exponents.

99=3⋅11

Final Answer

99=3⋅11

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