Find the Prime Factorization 150

Problem

150

Solution

1. Divide by the smallest prime, which is 2 Since 150 is even, it is divisible by 2

150÷2=75

2. Divide by the next smallest prime, which is 3 Since the sum of the digits of 75 (7 + 5 = 12)i*s(d(i))*v*i*s(i)*b*l*e*b*y,5i*s(d(i))*v*i*s(i)*b*l*e*b*y$.

75÷3=25

3. Divide by the next smallest prime, which is 5 Since 25 ends in 5 it is divisible by 5

25÷5=5

4. Identify the final prime factor, which is 5 Since 5 is a prime number, the process is complete.

5÷5=1

5. Collect all prime factors used in the divisions to write the final expression.

2⋅3⋅5⋅5=2⋅3⋅5

Final Answer

150=2⋅3⋅5

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