Find the Exact Value arccos(-1/2)
Problem
Solution
Identify the range of the inverse cosine function, which is
[0,π] Set the expression equal to an angle
θ such thatcos(θ)=−1/2 where0≤θ≤π Determine the reference angle in the first quadrant where
cos((θ_ref))=1/2 which isπ/3 Locate the angle in the second quadrant because the cosine value is negative and the range is
[0,π] Calculate the angle using the formula
θ=π−(θ_ref) Simplify the expression
π−π/3 to find the final value.
Final Answer
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