Find the Domain x+5a- square root of 2b=1

Problem

x+5*a−√(,2*b)=1

Solution

1. Identify the variable for which the domain is being determined. In an equation involving x a and b the domain typically refers to the set of possible values for the independent variable x that make the equation well-defined.

2. Analyze the structure of the equation. The expression x+5*a−√(,2*b)=1 is a linear equation with respect to x

3. Check for restrictions such as denominators that could be zero or even-indexed roots with negative radicands. The term √(,2*b) requires 2*b≥0 for the equation to exist in the real number system, but this is a condition on the parameter b not on x

4. Determine the constraints on x Since x is not inside a square root, not in a denominator, and not inside a logarithm, there are no algebraic restrictions on the values x can take.

5. Conclude that x can be any real number.

Final Answer

Domain: *(−∞,∞)

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