Find the Domain 1/(6k^2)=1/(3k^2)-1/k

Problem

1/(6*k2)=1/(3*k2)−1/k

Solution

1. Identify the denominators in the equation, which are 6*k2 3*k2 and k

2. Set each unique denominator expression equal to zero to find the values that must be excluded from the domain, as division by zero is undefined.

3. Solve the equation k2=0 and k=0 which both result in k=0

4. State the domain as all real numbers except for the values that make the denominators zero.

Final Answer

Domain: *{[k∈ℝ,k≠0]}

Want more problems? Check here!