Find the Derivative - d/dx y=sin(3x)
Problem
Solution
Identify the outer function as
sin(u) and the inner function asu=3*x Apply the chain rule, which states that the derivative of
ƒ*(g(x)) isƒ′*(g(x))⋅g(x)′ Differentiate the outer function
sin(u) with respect tou to getcos(u) Differentiate the inner function
3*x with respect tox to get3 Multiply the results together and substitute
3*x back in foru
Final Answer
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