Find the Derivative - d/dx y=arcsin(x/2)
Problem
Solution
Identify the outer function as
arcsin(u) and the inner function asu=x/2 Apply the chain rule which states that
d(y)/d(x)=d(y)/d(u)⋅d(u)/d(x) Differentiate the outer function using the rule
d(arcsin(u))/d(u)=1/√(,1−u2) Differentiate the inner function
d()/d(x)x/2=1/2 Combine the derivatives using the chain rule.
Simplify the expression inside the square root.
Find a common denominator inside the square root.
Simplify the radical by taking the square root of the denominator.
Multiply the fractions to reach the final simplified form.
Final Answer
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