Find the Derivative - d/dx natural log of cos(3x)
Problem
Solution
Identify the outer function as
ln(u) whereu=cos(3*x) Apply the chain rule for the natural logarithm, which states
d(ln(u))/d(x)=1/u⋅d(u)/d(x) Differentiate the inner function
u=cos(3*x) using the chain rule again, where the derivative ofcos(v) is−sin(v)⋅d(v)/d(x) Calculate the derivative of the innermost argument
3*x which is3 Combine the results of the chain rule steps.
Simplify the expression using the trigonometric identity
sin(θ)/cos(θ)=tan(θ)
Final Answer
Want more problems? Check here!