Find the Derivative - d/dx natural log of 1-x
Problem
Solution
Identify the outer function as
ln(u) and the inner function asu=1−x Apply the chain rule, which states that
d(ln(u))/d(x)=1/u⋅d(u)/d(x) Differentiate the inner function
1−x with respect tox which results in−1 Substitute the inner function and its derivative back into the chain rule formula.
Simplify the resulting expression by multiplying the terms.
Final Answer
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