Find the Derivative - d/dx arctan(sin(x))
Problem
Solution
Identify the outer function as
ƒ(u)=arctan(u) and the inner function asu=sin(x) Apply the chain rule, which states that
d(ƒ(u))/d(x)=d(ƒ)/d(u)⋅d(u)/d(x) Differentiate the outer function with respect to
u using the ruled(arctan(u))/d(u)=1/(1+u2) Differentiate the inner function with respect to
x using the ruled(sin(x))/d(x)=cos(x) Substitute the expressions back into the chain rule formula.
Simplify the expression by multiplying the terms.
Final Answer
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