Find the Critical Points f(x)=3x^2-12x-8

Problem

ƒ(x)=3*x2−12*x−8

Solution

1. Find the derivative of the function ƒ(x) with respect to x using the power rule.

d(ƒ(x))/d(x)=6*x−12

2. Set the derivative equal to zero to find the values of x where the slope of the tangent line is horizontal.

6*x−12=0

3. Solve for x by isolating the variable on one side of the equation.

6*x=12

4. Divide both sides by 6 to find the critical value.

x=2

Final Answer

x=2

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