Find Amplitude, Period, and Phase Shift y=5sin(3x-pi)

Problem

y=5*sin(3*x−π)

Solution

1. Identify the standard form of the trigonometric function y=A*sin(B*(x−C))+D or y=A*sin(B*x−C)+D

2. Determine the amplitude by taking the absolute value of the coefficient A

|A|=|5|

Amplitude=5

3. Calculate the period using the formula P=(2*π)/B where B=3

P=(2*π)/3

4. Find the phase shift by setting the argument of the sine function to zero and solving for x or using the formula C/B

3*x−π=0

3*x=π

x=π/3

Final Answer

Amplitude=5,Period=(2*π)/3,Phase Shift=π/3

Want more problems? Check here!