Find Amplitude, Period, and Phase Shift d=2sin(pi/3t)

Problem

d=2*sin(π/3*t)

Solution

1. Identify the standard form of the trigonometric function, which is d=A*sin(B*(t−C))+D or d=A*sin(B*t−C)+D

2. Determine the amplitude by taking the absolute value of the coefficient A

|A|=|2|

A=2

3. Calculate the period using the formula P=(2*π)/|B| where B is the coefficient of t

B=π/3

P=(2*π)/π/3

P=6

4. Find the phase shift by identifying the horizontal displacement C Since there is no constant added to or subtracted from the t term inside the sine function, the phase shift is zero.

C=0

Final Answer

Amplitude=2,Period=6,Phase Shift=0

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