Factor y^2-10y+25

Problem

y2−10*y+25

Solution

1. Identify the structure of the quadratic expression, which is in the form a*y2+b*y+c where a=1 b=−10 and c=25

2. Recognize that the expression is a perfect square trinomial because the first term is y2 the last term is 5 and the middle term is −2*(y)*(5)

3. Apply the formula for a perfect square trinomial, which states a2−2*a*b+b2=(a−b)2

4. Substitute a=y and b=5 into the formula to obtain the factored form.

Final Answer

y2−10*y+25=(y−5)2

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