Factor x^3+3x^2+4x+12

Problem

x3+3*x2+4*x+12

Solution

1. Group the terms into two pairs to prepare for factoring by grouping.

(x3+3*x2)+(4*x+12)

2. Factor out the greatest common factor from each pair.

x2*(x+3)+4*(x+3)

3. Factor out the common binomial (x+3) from the expression.

(x+3)*(x2+4)

Final Answer

x3+3*x2+4*x+12=(x+3)*(x2+4)

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