Factor x^2+4x-12

Problem

x2+4*x−12

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c where a=1 b=4 and c=−12

2. Find two numbers that multiply to the constant term c=−12 and add to the linear coefficient b=4

3. Determine the pair of numbers by testing factors of −12 the numbers 6 and −2 satisfy both conditions because 6⋅(−2)=−12 and 6 + (-2) = 4$.

4. Write the factored form using these numbers as (x+p)*(x+q)

Final Answer

x2+4*x−12=(x+6)*(x−2)

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