Factor x^2+3x-18

Problem

x2+3*x−18

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c where a=1 b=3 and c=−18

2. Find two numbers that multiply to c (which is −18 and add to b (which is 3.

3. Determine the factors by testing pairs of numbers that multiply to −18 6 and −3 satisfy both conditions because 6⋅(−3)=−18 and 6 + (-3) = 3$.

4. Write the expression in factored form (x+p)*(x+q) using the numbers found.

Final Answer

x2+3*x−18=(x+6)*(x−3)

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