Factor x^2+22x+121

Problem

x2+22*x+121

Solution

1. Identify the structure of the quadratic expression, which is in the form a*x2+b*x+c where a=1 b=22 and c=121

2. Recognize that the expression may be a perfect square trinomial because the first term x2 is the square of x and the last term 121 is the square of 11

3. Verify the middle term by checking if 22*x is equal to 2⋅x⋅11

4. Apply the formula for a perfect square trinomial, a2+2*a*b+b2=(a+b)2 where a=x and b=11

Final Answer

x2+22*x+121=(x+11)2

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