Factor x^2+14x+48

Problem

x2+14*x+48

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c where a=1 b=14 and c=48

2. Find two numbers that multiply to c (48 and add to b (14.

3. List the factor pairs of 48 (1,48) (2,24) (3,16) (4,12) and (6,8)

4. Select the pair (6,8) because 6×8=48 and 6 + 8 = 14$.

5. Write the factored form using these two numbers as (x+p)*(x+q)

Final Answer

x2+14*x+48=(x+6)*(x+8)

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