Factor x^2-20x+100

Problem

x2−20*x+100

Solution

1. Identify the structure of the quadratic expression, which is in the form a*x2+b*x+c where a=1 b=−20 and c=100

2. Recognize that the expression is a perfect square trinomial because the first term is x2 the last term is 10 and the middle term is −2*(x)*(10)

3. Apply the formula for a perfect square trinomial, which states that a2−2*a*b+b2=(a−b)2

4. Substitute a=x and b=10 into the formula to obtain the factored form.

Final Answer

x2−20*x+100=(x−10)2

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