Factor p^2+3p-18

Problem

p2+3*p−18

Solution

1. Identify the coefficients of the quadratic expression in the form a*p2+b*p+c where a=1 b=3 and c=−18

2. Find two numbers that multiply to c (which is −18 and add to b (which is 3.

3. Determine the factors by testing pairs of numbers that multiply to −18 6 and −3 satisfy both conditions because 6×−3=−18 and 6 + (-3) = 3$.

4. Write the expression in factored form (p+r)*(p+s) using the numbers found.

Final Answer

p2+3*p−18=(p+6)*(p−3)

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