Factor 9x^2+18x+8

Problem

9*x2+18*x+8

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c where a=9 b=18 and c=8

2. Find two numbers that multiply to a*c (which is 9×8=72 and add to b (which is 18.

3. Determine the pair of numbers, which are 6 and 12 since 6×12=72 and 6 + 12 = 18$.

4. Rewrite the middle term 18*x using the two numbers found: 9*x2+6*x+12*x+8

5. Factor by grouping by taking the greatest common factor out of the first two terms and the last two terms: 3*x*(3*x+2)+4*(3*x+2)

6. Factor out the common binomial (3*x+2) to obtain the final factored form.

Final Answer

9*x2+18*x+8=(3*x+2)*(3*x+4)

Want more problems? Check here!