Factor 9x^2-48x+64

Problem

9*x2−48*x+64

Solution

1. Identify the structure of the quadratic expression a*x2+b*x+c and check if the first and last terms are perfect squares.

2. Recognize that 9*x2 is (3*x)2 and 64 is 8

3. Verify if the middle term fits the pattern for a perfect square trinomial, which is −2*a*b

4. Calculate the middle term using a=3*x and b=8

−2*(3*x)*(8)=−48*x

5. Apply the formula for a perfect square trinomial (a−b)2=a2−2*a*b+b2

6. Substitute the values into the formula to get (3*x−8)2

Final Answer

9*x2−48*x+64=(3*x−8)2

Want more problems? Check here!