Factor 5x^2+19x-4

Problem

5*x2+19*x−4

Solution

1. Identify the coefficients of the quadratic expression a*x2+b*x+c where a=5 b=19 and c=−4

2. Find two numbers that multiply to a*c=5⋅(−4)=−20 and add to b=19

3. Determine the pair of numbers, which are 20 and −1 since 20⋅(−1)=−20 and 20 + (-1) = 19$.

4. Rewrite the middle term 19*x using these two numbers: 20*x−x

5*x2+20*x−x−4

5. Factor by grouping the first two terms and the last two terms.

5*x*(x+4)−1*(x+4)

6. Factor out the common binomial (x+4)

(5*x−1)*(x+4)

Final Answer

5*x2+19*x−4=(5*x−1)*(x+4)

Want more problems? Check here!