Factor 4x^2-81

Problem

4*x2−81

Solution

1. Identify the expression as a difference of two squares, which follows the pattern a2−b2=(a−b)*(a+b)

2. Rewrite the first term 4*x2 as a perfect square: (2*x)2

3. Rewrite the second term 81 as a perfect square: 9

4. Apply the formula for the difference of squares using a=2*x and b=9

Final Answer

4*x2−81=(2*x−9)*(2*x+9)

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