Factor 3x^2+8x+16

Problem

3*x2+8*x+16

Solution

1. Identify the coefficients of the quadratic expression in the form a*x2+b*x+c Here, a=3 b=8 and c=16

2. Calculate the discriminant to determine if the quadratic is factorable over the set of rational numbers.

D=b2−4*a*c

D=8−4*(3)*(16)

D=64−192

D=−128

3. Analyze the result. Since the discriminant is negative, the quadratic has no real roots and cannot be factored into linear factors with real coefficients.

4. Conclude that the expression is irreducible over the real numbers.

Final Answer

3*x2+8*x+16=irreducible

Want more problems? Check here!